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Solve x² + 7x + 2 = 0
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you mean x² + 7x + 12 = 0 ????????
Use the quadratic equation: a=1 b=7 c=2 \[-7 \pm \sqrt{7^{2}-4(1)(2)}/(2(1))=-7 \pm \sqrt{49-8}/2=-7 \pm \sqrt{41}/2\]
Here, a = 1, b = 7 and c = 12 As: \[D = b^2 - 4ac\] So, from here can you find D???
how do you know it is a 12?
Sorry, Little mistake.. c = 2
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i just thought is it 12 ???
yes or no ???
no
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