Question

Write an equation in point slope form of the line that passes through (5, 0), and whose slope is -2.


y = -2(x – 5)

y – 5 = -2(x - 5)

y = -2(x + 5)

y = 2(x – 5)

Answer 1

y=mx+c

Answer 2

You have the slope and a points, plug them in \(y=mx+c\)

Answer 3

here m= -2, put (5,0) at the place of x and y and solve for c

Answer 4

Find c

\(y=mx+c \\
0=-2(5)+c\\
0=-10+c\\
0--10=c\\
c=10\)

Answer 5

\(y=-2x+10\)

Factor -2 out.

\(y=-2(x-5)\)