Write an equation in point slope form of the line that passes through (5, 0), and whose slope is -2.

y = -2(x – 5)

y – 5 = -2(x - 5)

y = -2(x + 5)

y = 2(x – 5)

Question

Write an equation in point slope form of the line that passes through (5, 0), and whose slope is -2.
 
		
y = -2(x – 5)
 		
y – 5 = -2(x - 5)
 		
y = -2(x + 5)
 		
y = 2(x – 5)

anonymous · Answer

y=mx+c

zepp · Answer

You have the slope and a points, plug them in $y=mx+c$

anonymous · Answer

here m= -2, put (5,0) at the place of x and y and solve for c

zepp · Answer

Find c

$y=mx+c \
0=-2(5)+c\
0=-10+c\
0--10=c\
c=10$

zepp · Answer

$y=-2x+10$

Factor -2 out.

$y=-2(x-5)$