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can someone show the steps and answer to this problem i did it wrong and im confused (x + 6)(x − 6) and (x − 6)(x − 6)
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(x+6)(x-6) you can use the identity \[(a+b)(a-b)=a^2-b^2 \]
here a =x & b= 6
Just substitute the values :)
can you try that?
(x+6)(x-6)=x^2-6x+6x-36=x^2-36 (x-6)(x-6)=x^2-12x+36
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