If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation. x-2y=17
x+3y=17
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jimthompson5910 (jim_thompson5910):
Basically they want you to solve for x in the first equation. Then you replace 'x' in the second equation with whatever you got after you solved for x.
OpenStudy (anonymous):
I still don't know how to do that /:
jimthompson5910 (jim_thompson5910):
can you solve x-2y=17 for x?
OpenStudy (anonymous):
x=2y +17 ??
jimthompson5910 (jim_thompson5910):
you got it
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jimthompson5910 (jim_thompson5910):
now go to the second equation
x+3y = 17
and replace 'x' with '2y+17' (since the two are equal) to get
(2y+17)+3y = 17
2y+17+3y = 17
OpenStudy (anonymous):
The options are ..
(2y+2)+3y=17
(-2y+2)+3y=17
x+3(2y+2)=17
x+3(-2y+2)=17
jimthompson5910 (jim_thompson5910):
So it's (2y+17)+3y = 17, which is shown above
jimthompson5910 (jim_thompson5910):
oh wait, hold on
jimthompson5910 (jim_thompson5910):
hmm there must be a typo in the first equation
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jimthompson5910 (jim_thompson5910):
can you double check?
OpenStudy (anonymous):
ooops , My bad . It's x-2y=2
jimthompson5910 (jim_thompson5910):
so x = 2y+2
jimthompson5910 (jim_thompson5910):
and
x+3y = 17
becomes
(2y+2)+3y = 17
OpenStudy (anonymous):
Thanks & If I was trying to choose a new equation equivalent to y...
15x -y=-6
5x-3y=17
How would I do that ?
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jimthompson5910 (jim_thompson5910):
notice we have 15x-y = -6, what do we get when we solve for y?
OpenStudy (anonymous):
y=15x+6 ?
jimthompson5910 (jim_thompson5910):
you got it
jimthompson5910 (jim_thompson5910):
Now jump to the other equation 5x-3y=17 and replace y with 15x+6 to get
5x-3(15x+6)=17
OpenStudy (anonymous):
ThankYOU !(:
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