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integral of x^3/(x^2+8) I need help with the long division please...
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I'm really bad at long division with variables, any help would be appreciated :)
x ------------------- x^2 + 8 ) x^3 x^3 + 8x -------- - 8x = x - 8x ------ x^2 + 8
where do we get the 'x' for the 8x, from the x we got from x^2 into x^3?
we multiply x^2 + 8 by x ( the x above the ----) to give x^3 + 8x subtracting that from x^3 gives us the - 8x
- now i understand what you said - the answer is yes
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how do we integrate the 8x/ x^2 + 8? |dw:1340401057192:dw|
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