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Mathematics 8 Online
OpenStudy (anonymous):

What is the equation of this circle?

OpenStudy (anonymous):

OpenStudy (anonymous):

(x + 1)2 + y2 = 2 (x – 1)2 + y2 = 4 (x + 1)2 + y2 = 4 (x – 1)2 + y2 = 2

OpenStudy (campbell_st):

centre is (-1, 0) and r = 2 the general form of a circle is (x -h)^2 + (y - k)^2 = r^2 centre (h, k) radius r hope this helps

OpenStudy (anonymous):

is it (x – 1)2 + y2 = 2 @campbell_st

OpenStudy (campbell_st):

remember if you have r the equation uses r^2

OpenStudy (anonymous):

(x – 1)2 + y2 = 4?

OpenStudy (campbell_st):

the equation is (x - (-1))^2 + (y - 0)^2 = 2^2 or (x +1)^2 + y^2 = 4

OpenStudy (anonymous):

thnks

OpenStudy (campbell_st):

hope it helps

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