Question

find the equation of the circle with center at (1,2) that passes through the points (-2,-1)

Answer 1

First find the radius by finding the distance from (1,2) to (-2,-1)

Answer 2

Then plug the center (h,k) and radius r into this equation:
\[(x-h)^2+(y-k)^2=r^2\]

Answer 3

Find the radius by using the distance formula to find the distance between the provided points.
\[d=\sqrt{\left( x _{2}-x _{1} \right)^{2}+\left( y _{2}-y _{1} \right)^{3}}\]

Answer 4

i gor r=4.24

Answer 5

that's right.

Answer 6

so plug r, h, and k into the equation mertsj put up