Question

(x^2+2x-3)/(x^2-9)

Answer 1

\[\frac{x^{2} + 2x - 3}{x^{2} - 9} = \frac{(x + 3)(x - 1)}{(x + 3)(x - 3)} = \frac{\cancel{(x + 3)}(x - 1)}{\cancel{(x + 3)}(x - 3)} = \frac{x - 1}{x - 3}\]