Question

x^2+16=8x

Answer 1

solve it for zero; i.e. rearrange this into the form\[ax^2+bx+c=0\]what do you get ?

Answer 2

x=4. took me forever to figure it out! have to subtract -8x on each side. which gives u x^2-8x+16=0 (x-4)(x-4). x-4=0 x-4=0 add four to each side. x=4!