Question

2ndderivative of xcosa+ysina=p,

Answer 1

I must say any more information

Answer 2

that's just the given.. eliminating the arbitrary constant is the goal..

Answer 3

ok ok

Answer 4

ySin(a)=p-xCos(a)
y=(1/Sina)(p-xCos(a))
I'm assuming x is the only variable.

Answer 5

y'=(1/Sina)(-Cos(a))
y''=0

Answer 6

or maybe it's p(a)

Answer 7

What is it?
y(x), y(a), x(a), p(x), p(y), etc... you choose

Answer 8

well it could be y-2=xcos(a)+y-2=0

Answer 9

We'll differentiate!

Answer 10

umm....

Answer 11

o isee now it is ySin(a)=p-xCos(a) y=(1/Sina)(p-xCos(a)

Answer 12

y''sina=0