Question

Use synthetic division to find the quotient and remainder when \[x^6-1\] is divided by \[x+1\]

Answer 1

\[\huge{(x^3)^2-(1)^2=[{(x^3)+1}][{x^3-1}]}\]

Answer 2

\[x^6-1=(x^5)(x+1)-2\]

Answer 3

What did you do @mathslover