Question

Find the equation of the line passing through the point (-6,13) which is parallel tot he line 8x+3y-14=0

Answer 1

\[3y=-8x+14\]
\[y=-\frac{8}{3}x+\frac{14}{3}\]
\[m=-\frac{8}{3}x\]
\[y-y_1=m(x-x_1)\]
\[y-13=-\frac{8}{3}(x+6)\]
\[3y-39=-8(x+6)\]
\[3y-39=-8x-6\]
\[3y+8x+9=0\]

Answer 2

its perfect !!

Answer 3

Thanks for your response!