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how do you get the ? in (3x-7/12-3x) (3x-12/?)=1
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\[\frac{3x-7}{12-3x} \times \frac{3x-12}{?}=\frac{3x-7}{12-3x} \times \frac{-1(12-3x)}{?}=\frac{3x-7}{\cancel {12-3x}}\times \frac{-1\cancel{(12-3x)}}{?}=\frac{7x-3}{?}=1.\]
\[\implies \frac{7-3x}{?}=1 \implies ?=\frac{7-3x}{1}=7-3x.\]
Any doubt?
why did it become 7-3x?
Becoz...... \[(3x-7)\times (-1)= (7-3x).\]
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owwww
now tell me if any doubt.
thanks--i have no doubt,,thanks again--you are a genius
I omg ---no genius:) yw:)
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