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Mathematics 17 Online
Parth (parthkohli):

How will we solve this? What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?

Parth (parthkohli):

@FoolForMath I need your genius here

OpenStudy (ash2326):

50!.... 5! each of these have a 5! so remainder will be 4!+3!+2!+1!=24+6+2+1=33

Parth (parthkohli):

I am not sure how you got it :|

OpenStudy (anonymous):

It's easy, Starting from 5! every factorial is a divisible by 5.

OpenStudy (anonymous):

So, just ignore the rest.

Parth (parthkohli):

Oh yes!

OpenStudy (ash2326):

Did you understand @ParthKohli ?

Parth (parthkohli):

Yes! that's the principle of how we divide \(\Large {6! \over 5!}\) and we get \(6\)... so 6 is the quotient and there is no remainder! ^.^

OpenStudy (anonymous):

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