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It is claimed that two cesium clocks, if allowed to run for 100 years, free from any disturbance, may differ by only about 0.02 s. What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of 1 s?
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100*365*24*60*60
leap year so +25
so 0.02/100*365*24*60*60+25
yup i got it plzz look my new question..
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