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if theta = cot^-1 7 + cot ^-1 8 + cot ^-1 18 , then cot theta is =?
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\[\cot^{-1}x + \cot^{-1} y = \cot^{-1}(xy - 1)/(x + y)\] You have to use this Inverse Trigonometric Identity to get your answer...
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