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Mathematics 17 Online
OpenStudy (anonymous):

Rearranging formula. http://tnypic.net/32b57.jpg

OpenStudy (anonymous):

I have to get a= Which I did, however, it's different from the given solution.

OpenStudy (anonymous):

I got a=-bux1/(x0-x1)

OpenStudy (anonymous):

solution given has it as \[a=bux _{1}/(x1-x0)\]

OpenStudy (anonymous):

I must be doing something stupidly wrong.

OpenStudy (anonymous):

multiply and divide by -1

OpenStudy (anonymous):

Ok so that will just change the signs

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

but the x0 and x1 are still reserved.

OpenStudy (anonymous):

what is (a-b)*(-1)???? its b-a....do the same thing for the denominator...... nd (-a)*(-1)=a

OpenStudy (anonymous):

do that for numerator

OpenStudy (anonymous):

Thnaks for the help, back to class for me.

OpenStudy (anonymous):

no biggie!!!

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