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Mathematics 11 Online
OpenStudy (anonymous):

Let a and b be two real numbers

OpenStudy (anonymous):

Just real numbers

OpenStudy (anonymous):

my answer was for positive real numbers i will try for all real numbers

OpenStudy (anonymous):

@ toogoo131 \[the \ answer \ is \ \frac{a+b+\left| a-b \right|}{2} \\ \]

OpenStudy (anonymous):

\[if \ a >b \ \ \ \ \ \frac{a+b+\left| a-b \right|}{2}=\frac{a+b+a-b}{2}=\frac{2a}{2}=a \\ if \ b >a \ \ \ \ \ \frac{a+b+\left| a-b \right|}{2}=\frac{a+b+b-a}{2}=\frac{2b}{2}=b\]

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