Question

loop program to display this:
Enter height: 5
* *
* *
*
* *
* *

Answer 1

what do you have so far?

Answer 2

I think I know the answer ;)

Answer 3

i have this, it's different, i can't seem to change the loop statement :(
#include <iostream.h>
#include <conio.h>
int main()
{
int number=0;
int counter1=0;
cout<<"Enter the size of the shape: ";
cin >> number;
counter1=-number;
while(counter1 <=number)
{
for (int counter2 = -number; counter2 <= number; ++counter2)
{
if (abs(counter1) == abs(counter2))
{
cout<<"x";
}
else
{
cout<<" ";
}
}
++counter1;
cout<<endl;
}
getche ();
return 0;
}

Answer 4

have you tried drawing it out with a regular pen and paper for these cases? : height = 1, 2,3 ?

Answer 5

yup, for example when i enter 3
x x
x x
x x
x
x x
x x
x x

Answer 6

i got a new set of codes, but still not working, i can't figure out what is wrong :(
#include <iostream.h>
#include <math.h>
#include <conio.h>
int main()
{
int num, length;
clrscr();
cout<<"Enter the size: ";
cin >> length;
num=length
for(int i=1; i<length; i++)
{
for(int j=1; j<length; j++)
{
if((i==j) && (j==num))

cout<<"*";
else
cout<<" ";
}
num--;
cout<<endl;
}
getche ();
return 0;
}

Answer 7

^ tl;dr summary : think about it some more... work it out with pen and paper on what the computer is actually doing.

Answer 8

try this :
#include <iostream.h>
#include <conio.h>
int main()
{
int number=0;
int counter1=0;
cout<<"Enter the size of the shape: ";
cin >> number;
counter1=-number\(/2\);
while(counter1 <=number)
{
for (int counter2 = -number\(/2\); counter2 <= number\(/2\); ++counter2)
{
if (abs(counter1) == abs(counter2))
{
cout<<"x";
}
else
{
cout<<" ";
}
}
++counter1;
cout<<endl;
}
getche ();
return 0;
}