Question

Find the absolute and local maximum and minimum values of f(x)=6x^2 ,0 13 years ago

Answer 1

the quadratic \(f(x)=6x^2\) is a parabola that opens up, with vertex at the origin

Answer 2

so absolute max is at \(x=5\), as is the local max
unfortunately there is not absolute min or local min. it would be at \(x=0\) but this is not in the domain since you are restricted to \(0<x\leq 5\) so there is no min, absolute or local