Question

x^2/9 - y^2/16 = 1. Find the asymptotes please! I already found center at the origin, vertices (3,0),(-3,0) and the foci at (5,0) , (-5,0).. thanks please!!

Answer 1

Is it y=+/- (16/9)x ?

Answer 2

I think it's y = ±4/3x

Answer 3

Okay you're sure?

Answer 4

Well, if you want, you can call someone here. Put @ and then put the username. I'm pretty sure I'm right though.

Answer 5

Okay thanks