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OpenStudy (anonymous):
x^2/9 - y^2/16 = 1. Find the asymptotes please! I already found center at the origin, vertices (3,0),(-3,0) and the foci at (5,0) , (-5,0).. thanks please!!
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OpenStudy (anonymous):
Is it y=+/- (16/9)x ?
OpenStudy (anonymous):
I think it's y = ±4/3x
OpenStudy (anonymous):
Okay you're sure?
OpenStudy (anonymous):
Well, if you want, you can call someone here. Put @ and then put the username. I'm pretty sure I'm right though.
OpenStudy (anonymous):
Okay thanks
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