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Mathematics 19 Online
OpenStudy (anonymous):

Show that if A is nxn and has all 0’s on and below the diagonal then An = 0. Hint: do not at first be too ambitious. First find A2 and observe something useful about it. What about A3?

myininaya (myininaya):

What is An?

OpenStudy (anonymous):

the matrix

OpenStudy (anonymous):

commonly seen as Ax=b. this is An=0.

myininaya (myininaya):

Oh I thought there might have been a difference because you called the matrix A then you called it An

myininaya (myininaya):

Are you saying n is an eigenvector ?

OpenStudy (anonymous):

honesly i dont know wat to do. this is what the teacher asked us

myininaya (myininaya):

Or are you say An is the matrix?

OpenStudy (anonymous):

idk..lol

myininaya (myininaya):

Ok I think |dw:1340595284758:dw| and |dw:1340595304816:dw|

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