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OpenStudy (anonymous):
find the smallest number by which 9408 must be divided so that it becomes a perfect square so obtained
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OpenStudy (foolaroundmath):
\[9408 = 2^{6}.3^{1}.7^{2}\] For a number to be a perfect square, the exponents should be even numbers. Note that the exponent of 3 is 1 which is odd. So, if we divide 9408 by 3, it becomes a perfect square
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