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5x/7-1/4=9/28
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To solve for x, you need to get it alone. Start by adding 1/4 to both sides. What do you get?
5x/7+1/4=9/28+1/4?
Close, 5x/7 -1/4 +1/4 = 9/28 +1/4 (Remember, on the left hand side, you are trying to get rid of the 1/4 so you do the opposite and you have to show it.) So you get 5x/7 = 9/28 + 1/4 what is 9/28 +1/4?
\[\frac{5x}7-\frac14=\frac9{28} \] \[\frac{20x - 7}{28} = \frac9{28}\] \[=> 20x - 7 = 9\] \[=> 20x = 9+7 = 16\] \[=> x = \frac{16}{20} = \frac45\]
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