y varies inversely with x, and x=150 when y=30. Find the inverse variation equation and use it to find the value of x when y=90
a. 1/5
b. 9/5
c. 5
d. 5/9
PLEASE HELP ME!
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OpenStudy (anonymous):
y=k/x
to find k:
30=k/150
k=30*50=1500
so equation is:
y=1500/x
now finf value of x, when y =90
90=1500/x
x=1500/90 = 150/9
OpenStudy (anonymous):
so what that equal too? 5/9???
OpenStudy (anonymous):
150/9=50/3
OpenStudy (anonymous):
than what?
OpenStudy (anonymous):
that's it
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OpenStudy (anonymous):
but it doesn't match to any of the answers though
OpenStudy (anonymous):
ups, i made a mistake, :)
y=k/x
to find k:
30=k/150
k=30*150=4500
so equation is:
y=4500/x
now finf value of x, when y =90
90=4500/x
x=4500/90 = 450/9=50
OpenStudy (anonymous):
so then is it d??
OpenStudy (anonymous):
no, it's x=50, but it doesn't mach any answer. Are you sure that x=150 when y=30 and no
x=15 when y=30
OpenStudy (anonymous):
yeah i'm sure...
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OpenStudy (anonymous):
so x=50 is the answer
OpenStudy (anonymous):
so c???
OpenStudy (anonymous):
the most probable is c, becouse i think there is a mistake in the problem