Question

a rectangle parking lot has a lenth that is 7 yards greater than the width. the area of the parking lot is 330 . find the lenth and width.

Answer 1

let width be x
\[length = x+7\]
\[x(x+7)=330 \]
\[x^2+7x-330=0 \]
\[x^2+22x-15x-330 =0 \]
\[x(x=22)-15(x=22)=0 \]
\[(x-22)(x-15)=0 \]

\[x=-22\] or \[x= 15\]


ignore negative value of 22
The width is 15 yards.
the length will be 15+7 = 22 yards