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MIT 6.002 Circuits and Electronics, Spring 2007 7 Online
OpenStudy (anonymous):

Help with nodal analysis (pic in comment).

OpenStudy (anonymous):

OpenStudy (anonymous):

(6-Vx)/1k=I_0 and (6+3Vx)/1k+2m=-I_0+Vx/1k => (12+Vx)/1k+2m=0 => Vx=-14

OpenStudy (nick67):

\[V _{X}=-14V\]\[I _{0}=20mA\]

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