Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

Question

anonymous · Answer

find the smallest and substract it from phi*8^2

anonymous · Answer

the smallest one is 5.07 but idk how to do it

anonymous · Answer

tha way i told ya earlier...find the smallest ,subtract it and get the largest

anonymous · Answer

subratct it from what though?

anonymous · Answer

from phi*8^2

anonymous · Answer

my answer is suppost to be like this $$A = \left[\begin{matrix}? & ? \ ? & ?\end{matrix}\right] \pi + __\sqrt{_} ) inches 2$$

anonymous · Answer

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