Question

The perimeter of a rectangle is 34 feet. Find the width of the rectangle if the length is 5 feet more than twice the width.

Answer 1

let , width=w
therefore, length(l)=2w+5
now,
perimeter =2(l+b)
34=2(l+b)
34=2(2w+5+w)
34=2(3w+5)
34/2=3w+5
17=3w+5
17-5=3w
12=3w
12/3=w
4=w
so, width =4 feet

Answer 2

Thank you, I just wanted to check my answer and it was correct :-)

Answer 3

:)