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Write the equation of the circle with center at (0 , 0) and a radius of 6.
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\[(x - 0)^2 + (y - 0)^2 = 6^2\]Solve.
Sorry i dont need the answer i want is the formula or the process
\[(x - h)^2 + (y - k)^2 = r^2\] Where, (h,k) = Centre and r = Radius.. \[(x-0)^2 + (y - 0)^2 = 36\] And solve...
(x-h)^2 + (y-k)^2 = r^2
\[x ^{2}+y ^{2}= 36\]
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Yes you are right..
is this the answer?
your right. good.
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