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solve by factoring: 4x^2-9=0
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\[(2x)^2 - 3^2 = 0\] Can you use the formula now???
what formula would i use?
a^2-b^2=(a+b)(a-b)
\[(a^2 - b^2) = (a-b)(a+b)\]
is it (2x-3)(2x+3)=0
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Yes dear, you are right.. Now put separately both the factors = 0 (2x - 3) = 0 and (2x + 3) = 0 and now find x from here..
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