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One number is 7 more than another number. The sum of the numbers is 63. What are the numbers?
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\( \color{Black}{\Rightarrow x + (x + 7) = 63}\) Solve for x, and x + 7.
x=y+7 x-y=7 x+y=63 add both nd find the answer
Let the other number be : x So, First number = x + 7 And given: x + (x + 7) = 63 2x = 56 Solve for x..
that is 28 and 35 28+35=63
what about my answer?
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You've got your answer already...
some number = x some number +7 = x+7 now combine them to equal to 63 and solve for x. so we have, x+(x+7) = 63 x = 28 now since you know the value of one x the other would be 28 + 7 = 35
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