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factor the quadratic equation 0=a^2-4a+3
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break the middle term down into a^3 - a - 3a + 3 = 0 so it's easier to factor out
\[a^2 - 4a + 3 = 0\] \[a^2 - a - a + 3 = 0\] Take out common factors and then solve..
a^2-4a+3 = 0 a^2 - a - 3a + 3 = 0 Factor the left side first.
(x-1)(x-3) once you factorise it
soryy its (a-1)(a-3)
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Thanks for all the help I really appreciate it
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