Question

a gardener is planning to make a rectangular garden with an area of 80ft^2.she has 12 yards of fencing to put around the perimeter of the garden.what should the dimension of the garden be ?




please answer :))

Answer 1

please answer !! i need your help

Answer 2

you put yards into feets so units are the same and you can solve the problem by this equation system:

2a+2b=12 (put this number in feets)
a*b=80

Answer 3

huh ? Ivcvs , explain it further .. please

Answer 4

you solve the equation system for a and b, and you have the dimensions of the garden

Answer 5

a=length, b=width

Answer 6

so what is a and what is b ?

Answer 7

length yung a yung b width

Answer 8

pano mo nga makkha un ?

Answer 9

ung a at b ?

Answer 10

w8

Answer 11

?? xd

Answer 12

how to solve the a and the b

Answer 13

ah ok

Answer 14

by the way ty lvcvs

Answer 15

a=80/b; so we subsitute in first equation and we have;
2*(80/b)+2b=12;
160/b+2b=12;
160+2b^2/b=12;
160+2b^2=12b;
2b^2-12b+160=0;

here's a quadratic equation, do you know how to solve it?

Answer 16

hahahaha its difficult

Answer 17

we havent discussed it

Answer 18

can you please dicuss it to us ?? please ??

Answer 19

continue

Answer 20

excited ka pando

Answer 21

then ?

Answer 22

why is there 2 b ?

Answer 23

let the to sides be x nd y, so arey=x*y=80 and x+y=12/2=6 yards, now convert it into feets= 18 feets so x=18-y puttting in 1st equation, y(18-y)=80 clearly the asnwer is 8 nd 10