Question

Factor -2bk2 + 6bk - 2b.

Answer 1

here a = -2b and b = 6b and c =-2b

Answer 2

solve through quadratic equation :
\[\huge{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]

Answer 3

could you give the answer please

Answer 4

so u r giving test right ?

Answer 5

it is a quiz but i realy need to pass it

Answer 6

-2bk2 +6bk-2b
-2b(k^2 -3k +1)
apply the quadratic formula
the factors will be
\[3\div2 +\sqrt{5}\div2\]
\[3\div2 -\sqrt{5}\div2\]