Question

Indicate in standard form the equation of the line passing through the given points.

P(6, 2), Q(8, -4)

Answer 1

y=mx+c
m is gradient so m=(y1-y2)/(x1-x2)
m=(2-(-4))/(6-8)
m=-3
now, we put one point into equation,
so lets take P,
2=-3(6)+c
2=-18+c
20=c
so the equation is,
y=-3x+20