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OpenStudy (anonymous):
help!!!!
triangle ABC is a right triangle.the sides measure AB=6 and BC=8.use the Pythagorean theorm to find CA.
A.10
B.25
C.100
D.15
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OpenStudy (diyadiya):
\[\huge AC^2 = AB^2 + BC^2\]
This is the pythogorean theorem.
OpenStudy (anonymous):
|dw:1340723142847:dw|
OpenStudy (diyadiya):
Its basically states that squares of the legs of a right triangle add up to the square of the hypotenuse.
OpenStudy (anonymous):
is it c?
OpenStudy (diyadiya):
Can you show me how?
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OpenStudy (diyadiya):
\[\Large AC^2 = AB^2 + BC^2 \]\[\Large AC^2 = (6)^2 + (8)^2 \]
Remember
\(\Large AC \ne AC^2\) :)
OpenStudy (anonymous):
thats what i did.so it has to equal more than 100?
OpenStudy (diyadiya):
\[\Large AC^2 = 100\] this is what you got ,But you have to find \(\Large AC \) Not \(\Large AC^2 \)
How do you fins \(\Large AC \) Now?
OpenStudy (anonymous):
so its ten.because ten squared equals 100
OpenStudy (goformit100):
B.25 Ans.
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OpenStudy (diyadiya):
Right!!
\[\Large AC^2 = 100\]\[\Large \sqrt{AC^2} =\sqrt{100}\]\[\Large AC = 10\]
OpenStudy (diyadiya):
@goformit100 Please don't just give the final answer, If you think 25 is the answer, Please do explain. Thanks
OpenStudy (anonymous):
thank you!
OpenStudy (diyadiya):
You're Welcome :)
OpenStudy (anonymous):
can you help me with one more question?
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OpenStudy (diyadiya):
I'll try ,Post it!
OpenStudy (anonymous):
okay hang on one second!
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