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What is the solution to the equation 49^x = sqrt7^ (2x + 6)
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\[49^{x}=\sqrt{7}^{2x+6}\]
49^x =7^2x can you rewrite the right part in the same forme ?
x=3
so like 7 on what exponent ? and after this you need just make these exponents equales and from this you need calcule the x
sqrt7 = 7^(1/2) can you continue ?
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