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x=log(basea)bc , y=log(baseb)ca , z=log(basec)ab then 1+abc = ?
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little help how can you rewriting x using log base a ? x=logbasea of what ?
and y rewrite using log base b and z log base c so log base a note log(a) so than x=log(a) a^x =xlog(a) a because log(a) a =1 now is it ok ?
i am not getting anything sorry
@jhonyy9
will resulz a^x =bc b^y =ca c^z =ab using these relations you can calcule easy 1+abc= ...
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will result sorry
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