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OpenStudy (anonymous):
completely simplify 2ln e^(5x)
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OpenStudy (anonymous):
log and exp are inverse functions, meaning \(\ln(e^x)=x\)
OpenStudy (anonymous):
so would that be 10x or am i doing that completely wrong?
OpenStudy (anonymous):
yes it would be \(10x\) since \(\ln(e^{5x}) =5x\)
OpenStudy (anonymous):
ok. thanks so much
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