Question

For f(x)=log base 3 of (x-2), find f-1(x).

Answer 1

\[f(x)=\log_3(x-2)\]
\[y=\log_3(x-2)\]
now switch x and y and solve for y
\[x=\log_3(y-2)\] equivalent exponential form is
\[3^x=y-2\] add 2 and get
\[y=3^x+2\] or
\[f^{-1}(x)=3^x+2\]

Answer 2

great. thanks