Question

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104

Answer 1

use common ratio
t7/t6=a
t6/t5=a
.
.
.
t4/t3=a
t7=t3*\[t7=t3*a ^{4}\]
t7/t3=a^4
thus a=2

Answer 2

thus t6=t7/a=t7/2=3552
t5=t6/2=1776
t4=t5/2=888
t3=t4/2=444
t2=t3/2=222
t1=t2/2=111