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(4x^3 + 7y 3z^4)^2
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ok.
I'm just need to verify that you've posted the question properly. Why is there a gap between 7y and 3z ?
that is just how it showed up when I pasted it.
Okay, so that must mean that something should be there but it didn't show up, right ?
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no, its this (4x^3+7y^3z^4)^2
That what you just posted is significantly different from what you originally posted.
It shows that the y is cubed
okay.
(4x^3+7y^3z^4)^2 =4x^3(4x^3+7y^3z^4)+7y^3z^4(4x^3+7y^3z^4) =16x^6+42x^3y^3z^4+28x^3y^3z^4+49y^6z^8 =16x^6+70x^3y^3z^4+49y^6z^8
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