Question

A nice series problem, it may be helpful.
Calculate the sum of:

S[(2n+1)/(n+2)!]

n=1 to infinity

(An advice: use the serie for number e)

Answer 1

\[\sum_{1}^{\infty} (2n+1)/(n+2)!\]

Answer 2

I'm not asking, it's just for someone who wants to try

Answer 3

pretty trivial...\[\frac{7}{2}-e\]

I would write \(2n+1\) as \(2n+4-3=2(n+2)-3\)

Answer 4

True