Question

Plz help! D: i don't understand this one bit
Questions 14-16: Use this triangle to calculate the specified trigonometric values. http://is.byu.edu/courses/hs/GEOM-043-101/secure/imgs/math10-929.gif
14.Calculate sin
a. 7 over square root of 13
b. 6 over square root of 13
c. 6 over square root of 85
d. 7 over square root of 85
15.Calculate cos
a. 7 over square root of 13
b. 6 over square root of 13
c. 6 over square root of 85
d. 7 over square root of 85
16.Calculate tan
a. 7 over square root of 13
b. 6 over square root of 13
c. 6 over square root of 85
d. 7 over square root of 85

Answer 1

7/sqrt13 is what you plug into your calculator. then do it for all of them

Answer 2

Use Pythagorus to calculate the length of the hypotenuse of this triangle.
Then use trigonometry to calculate the values of sin, cos and tan of the indicated angle.

You might find this site useful if you want to brush up on trig: http://www.mathsisfun.com/algebra/trigonometry.html

Answer 3

i tried and i still dont dont know how -_-

Answer 4

use the link I gave you to learn about how to do these types of problems.
then post the steps you have attempted in trying to solve this and we will help you in the specific areas where you are having problems.

Answer 5

do you have a scientific calculator or graphing calculator?

Answer 6

either of those tools may help

Answer 7

i dont actually that is one of the reasons i cant do it

Answer 8

Hmm.. do you have a book then that may help you..?

Answer 9

this is all online

Answer 10

ah.. that does make it much harder.. :l

Answer 11

ya ur telling me and none of my family gets this either

Answer 12

Sin was the most difficult to learn online.. I don't even think I'll be much use.. :c I'm sorry..

Answer 13

its okay thanks for trying though

Answer 14

If you ever need my help for anything else I'll be glad to try.

Answer 15

thank you =)

Answer 16

you still confused?

Answer 17

This will help

http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry

This question 14 is asking you to find the sin of theta (labeled in the triangle)
you do not need a calculator.
The video is short and pretty good.

Answer 18

after watching the video i started to understand but then got more confused -_-

Answer 19

Ask pythagoras

Answer 20

watch the one after it also.

Answer 21

@pythagoras , please help...

Answer 22

well the first thing you do when you see an angle with two sides given like in your triangle, u immediately use your Pythagoras theorem to find the other side. this means you use this equation: \[a^2 +b^2=c^2\] c= the side of the triangle that is opposite to the 90 deg angle. so c in your triangle is the side that has no number. a and b in the equation are the other sides of the triangle... it does not matter which of those two sides you call a and which you call b as long as c is always named as the side opposite to the 90 deg angle. soooo.... in your example to find c.... you do this... 7^2 + 6^2=c^2.... which is 49+36=c^2... which is 85=c^2......to get rid of the square on the c you need to square root both sides... soo \\[\sqrt{85}=\sqrt{c^2}\]....therefore \[c=\sqrt{85}\]... so now you have all three sides... understand so far?

Answer 23

yes so far im understanding it

Answer 24

Oh my sole just typed an essay and computer froze:'( sorry ill type again just gimme a min...

Answer 25

okay ^_^

Answer 26

okay now that you have all your sides you can answer your questions. to answer you questions, you fisrt have to understand what sin cos and tan are... sin=O/H... cos =A/H.. and tan = O/A....

H is very similar to c.. H is always equal to the number that is opposite the 90deg angle... therefore H=c= \[\sqrt{85}\]

O stands for opposite. O is always the number opposite to the indicated angle that is NOT 90deg. this means that in your triangle.. O=7 because O equals the number opposite to the indicated angle that is not 90deg and that number is 7. the indicated angle in your triangle is the greek letter theta... but that doesnt matter.. just as long as you recognize that theta is an indicated angle.

A is the number that is not occupied on your triangle after you have assigned places for H and O. this means that in your triangle , A=6.

sooo... going back to sin=O/H... cos=A/H .. and tan=O/A

in question 14 they ask you to calculate sin. all they want you to do is find what O/H is equal to... now seeing as we said O=7 in your triangle and H=squareroot85.... then\[\sin =7/\sqrt{85}\] which is option d.

if you draw all the details that i gave you on your triangle, can you then try and tell me the answers to 15 and 16?

Answer 27

you following?

Answer 28

yes thank you

Answer 29

this has been the most helpful info i have gotten so far

Answer 30

its a pleasure... but question 16 is bogous... its completely wrong.. the answer should be 7/6. and that answer is not an option so either you got given the wrong info or you might have typed it in wrong but im 100% sure that the tan of that triangle =7/6... just letting you know so you dont get frustrated by Q 16 :)

Answer 31

ya i think i might have typed it wrong

Answer 32

hahahaha we all make mistakes , no biggie :) as long as you learned something and not still unsure :)

Answer 33

well im glad i understand the sin,cos, and tan thingy now XD

Answer 34

so am i coz that was a lot of typing haha :D

Answer 35

I KNOW I WAS LIKE ARE THEY TYPING ME A LETTER? :D

Answer 36

hahaha.... felt like it hahaha

Answer 37

ikr ^_^ but it was helpful and kinda funny in a way

Answer 38

im glad :)