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Mathematics 16 Online
OpenStudy (anonymous):

Factor Completely (special factoring/group solve by factoring) PLEASE EXPLAIN STEP BY STEP - Not Just Answer.... I'm trying to learn 15m^3+12m^2-375m-300

OpenStudy (campbell_st):

This is grouping in parts... select 15m^3 and 375m both have a common factor of 15m 12m^2 and 300 common factor of 12 which gives \[15m(m^2 - 25) - 12(m^2 - 25) \] now (m^2 - 25) is a common factor so its \[(15m - 12)(m^2 - 25) \] there are now more factoring that can be completed m^2 - 25 is the difference of 2 squares 15m - 12 have a common factor of 3 \[(15m - 12)(m^2 - 25) = 3(5m - 4)(m-5)(m+5)\]

OpenStudy (anonymous):

Thank you. I think I got it now.

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