Question

Need correction in finding the limit of g(x)
lim x->-2 g(x)= 3
lim x->-1+ g(x)=1
lim x->-1- g(x)= 2
lim x->-1 g(x)= dne
lim x->1+ g(x)=1
lim x->1- g(x)=1
lim x->1 g(x) dne

Answer 1

g(x)={-x+1 -3<x<=-1}
{1 -1<x<1}
{x^2 1<x<3}

Answer 2

use the domain restrictions to determine which "piece" to use to get the value...

Answer 3

first one is correct.

Answer 4

k

Answer 5

this is same thing i did in the previous question

Answer 6

but need to find limit of g(x)

Answer 7

everything is correct but that last one....