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Evaluate the following to the nearest tenth: √13
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\[\Large \sqrt{13} = 13^{0.5}\]
Id say, since sqrt13 is in between sqwrt 16 and 9, its value should also be more or less in between the two, but slightly closer to sqrt 16. Considering sqrt 16 and sqrt 9 are 4 and 3 respectively, sqrt 13 should be 3.6. Is this what you wanted?
would you like to try calculus for approximating sqrt(13) ?
I'm not doing calculus? lol Am i?
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