Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

(5c+2/3)(5c-2/3)

OpenStudy (anonymous):

((15c+2)(15c-2))/9

OpenStudy (anonymous):

I don't get it lol

OpenStudy (anonymous):

(5c*3+2)/3 * (5c*3-2)/3

OpenStudy (anonymous):

so it will become (15c+2)/3*(15c-2)/3

OpenStudy (anonymous):

=[(15c+2)(15c-2)]/9

OpenStudy (anonymous):

now u need to solve these two brackets by multiplyin them

OpenStudy (anonymous):

15c^2+4?

OpenStudy (anonymous):

no (15c)^2-4

OpenStudy (anonymous):

\[(5c+\frac{2}{3})(5c-\frac{2}{3})\]

ganeshie8 (ganeshie8):

hmm.. \((a+b)(a-b\)) = a^2-b^2

OpenStudy (anonymous):

use (a+b)(a-b)

OpenStudy (anonymous):

\[225c ^{2}-4\]/6

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!