three consecutive e… - QuestionCove
OpenStudy (anonymous):

three consecutive even integers are such that the square of the thrid is 76 more than the square of the second. find the three integers.

5 years ago
OpenStudy (anonymous):

Let the first even integer be : x Other will be : (x + 2) And third will be: (x + 4) $(x+4)^2 = 76 + (x+2)^2$ $(x+4)^2 - ( x+2 )^2 = 76$ Solve for x now..

5 years ago
OpenStudy (anonymous):

You can use the formula: $(a+b)^2 = a^2 + b^2 + 2ab$

5 years ago
OpenStudy (anonymous):

or we can call the middle one $$x$$ since the first one does not enter in to the question solve $x^2+76=(x+2)^2$ $x^2+76=x^2+4x+4$ $4x+4=76$ $4x=72$ $x=18$ so the three are $$\{16,18,20\}$$ and the smallest one is 16

5 years ago
OpenStudy (anonymous):

Is this a factoring method

5 years ago
OpenStudy (anonymous):

no factoring needed for this problem

5 years ago
OpenStudy (anonymous):

$x^2+76=(x+2)^2$ looks like it might be a quadratic equation, but it is not one because there is an $$x^2$$ on both sides, subtract it from both sides and you have a linear equation

5 years ago
OpenStudy (anonymous):

No factoring method, x squared terms will automatically cancel each other you have to solve for x and constant terms...

5 years ago
OpenStudy (anonymous):

just learning the quadratic formula trying to understand each method not to be confused. Thank you

5 years ago